I checked your calculation for (KOH) and it is correct at 0.06250 (rounded to 4 s.f.).
Then how many mols do you for 500 mL of the solution. If it is 0.06250 mols/L then for 1/2 L you will need 1/2 that = ?
Then grams KOH = mols KOH x molar mass KOH = ?
Q: 26.30mL of 0.1105 mol/L H3PO4 solution is neutralized by 139.50 mL of KOH.
Calculate the mass of solid KOH required to prepare 500.0 mL of this solution.
In the previous part of this question, it asked the concentration of KOH and I worked it out to be concentration of KOH is: 0.062497 mol/L
I don't know how to do that mass calculation.
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