Asked by Bella stoner
Q.250 cm3(cube) of the liquid weighs 125 grams. find the weight of 1000 cm3(cube) of the liquid.
Q.The cost of a long distance call lasting 20 seconds was 23.40 at this rate what was the cost of a call lasting 6 minutes 30 seconds.
Q.The cost of a long distance call lasting 20 seconds was 23.40 at this rate what was the cost of a call lasting 6 minutes 30 seconds.
Answers
Answered by
Jai
#1
to get this, we just use ratio and proportion.
let x = weight of 1000 cm^3 liquid.
250 cm^3 : 125 g = 1000 cm^3 : x g
thus we can rewrite this as,
250/125 = 1000/x
solving for x,
2 = 1000/x
2x = 1000
x = 500 grams
#2
here, we also use ratio and proportion. first we convert 6 min and 30 seconds to seconds:
6 min = 360 seconds
thus 360 + 30 = 390 seconds
let x = cost of 390 second call
20 : 23.4 = 390 : x
thus,
20/23.4 = 390/x
0.855 = 390/x
x = 390/0.855
x = 456.3
hope this helps~ :)
to get this, we just use ratio and proportion.
let x = weight of 1000 cm^3 liquid.
250 cm^3 : 125 g = 1000 cm^3 : x g
thus we can rewrite this as,
250/125 = 1000/x
solving for x,
2 = 1000/x
2x = 1000
x = 500 grams
#2
here, we also use ratio and proportion. first we convert 6 min and 30 seconds to seconds:
6 min = 360 seconds
thus 360 + 30 = 390 seconds
let x = cost of 390 second call
20 : 23.4 = 390 : x
thus,
20/23.4 = 390/x
0.855 = 390/x
x = 390/0.855
x = 456.3
hope this helps~ :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.