Put the function P= 35(1.3)^t in the form P0ekt When written in this form, you have:

Question

K=
P0=

Answer 1

at t=0, P=35, so Po is 35

P=35 e^kt
P=35(1.3)^t

dividing equations..
1=e^kt/(1.3)^t
or
1.3^t=e^kt
taking ln of each side
t*ln(1.3)=kt
k=ln(1.3)