Provide the balanced reaction, the value of K, and E(cell) at equilibrium for the for the electrochemical cell created

Question

from the two half-cell reactions below

Cr^(3+) + e ==> Cr^(2+)
Fe^(2+) + 2e ==> Fe

Well, I got the balanced reaction:
2Cr^(2+) + Fe^(2+) ==> Fe + 2Cr^(3+)

And the E(cell) = 0.06 V.

However, I have no idea how you could possibly solve for K. There doesn't seem to be enough information available to do that.

Help?

Answer 1

nFEocell = RTlnK

Answer 2

But you don't know the temperature...