H2O2(aq) + 2ClO2(g) → O2(g) + 2HClO2(aq)
O2 in H2O2 on the left is -2 for both O atoms. On the right O2 is zero. Loss of 2e.
2Cl on the left are +8 an on the right 2Cl in HClO2 are +6. Gain of 2e.
n must be 2, right?
The electrochemical cell described by the balanced chemical reaction has a standard emf (electromotive force) of 0.27 V. Calculate the equilibrium constant (Kc) for the reaction at 298 K. Round your answer to 3 significant figures.
H2O2(aq) + 2ClO2(g) → O2(g) + 2HClO2(aq)
i always do this problem wrong because i can never find the right n
and you use -RTlnK=-nFE0cell right?
2 answers
thank you Dr. Bob222, i don't know how you manage to answer everyone's questions but you are one amazing person :)