Prove that limit(z -> z_0) z^2 = z_0^2
I must show that for any positive number E that there exists a positive number delta so that whenever this is true:
0 < |z - z_0| < delta
then this is true:
|z^2 - z_0^2| < E
I must show that for any positive number E that there exists a positive number delta so that whenever this is true:
0 < |z - z_0| < delta
then this is true:
|z^2 - z_0^2| < E
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