Asked by dipti
prove that every every line segment has one and only one end point . use euclids geometry to prove
Answers
Answered by
Steve
it's false. A line segment is by definition finite in extent. So, it has two end points.
Since a line segment is non-directional, it makes no sense to call one end point a starting point.
A ray, on the other hand, has one end point, and extends indefinitely from it in a given direction.
Since a line segment is non-directional, it makes no sense to call one end point a starting point.
A ray, on the other hand, has one end point, and extends indefinitely from it in a given direction.
Answered by
pirya
Let us consider, a line segment AB.
Assume that it has two midpoints say C and D
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Recall that the midpoint of a line segment divides it into two equal parts
That is AC = BC and AD = DB
Since C is midpoint of AB, we have A, C and B are collinear
∴ AC + BC = AB → (1)
Similarly, we get AD + DB = AB → (2)
From (1) and (2), we get
AC + BC = AD + DB
2 AC = 2AD
∴ AC = AD
This is a contradiction unless C and D coincide.
Therefore our assumption that a line segment AB has two midpoints is incorrect.
Thus every line segment has one and only one midpoint.
Assume that it has two midpoints say C and D
�
Recall that the midpoint of a line segment divides it into two equal parts
That is AC = BC and AD = DB
Since C is midpoint of AB, we have A, C and B are collinear
∴ AC + BC = AB → (1)
Similarly, we get AD + DB = AB → (2)
From (1) and (2), we get
AC + BC = AD + DB
2 AC = 2AD
∴ AC = AD
This is a contradiction unless C and D coincide.
Therefore our assumption that a line segment AB has two midpoints is incorrect.
Thus every line segment has one and only one midpoint.
Answered by
Harsh
Tution kuch aur Pucha jata hai answer kuch aur batao
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