prove (tan^3x/1 tan^2x) (cot^3x/1 cot^2) = (1-2sin^2x cos^2x)/sinx cosx

1 answer

I assume the missing operators are +, and thus that you mean

tan^3x/(1+tan^2x) * cot^3x/(1+cot^2x)
= (1-2sin^2x cos^2x)/(sinx cosx)

but that is in fact not true. Maybe you can fix it up and try again.
Similar Questions
  1. Prove:sin2x / 1 - cos2x = cotx My Attempt: LS: = 2sinxcosx / - 1 - (1 - 2sin^2x) = 2sinxcosx / - 1 + 2sin^2x = cosx / sinx - 1 =
    1. answers icon 5 answers
  2. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
    1. answers icon 0 answers
  3. Q.1 Prove the following identities:-(i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii)
    1. answers icon 0 answers
  4. Q.1 Prove the following identities:-(i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii)
    1. answers icon 1 answer
more similar questions