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pankaj
Questions (15)
prove (tan^3x/1 tan^2x) (cot^3x/1 cot^2) = (1-2sin^2x cos^2x)/sinx cosx
1 answer
632 views
a body is moving with a velocity of 20 meter per second is apply abrack such that it stop in 2 second mass of body is 20 kg find
1 answer
520 views
csc x - cot x = root of 2 cot x then proof that csc x + cot x = root of 2 csc x
2 answers
500 views
which of the following langues was used in ashok 's rule?
3 answers
375 views
which of the following is a posioned gas?
option- (a)carbondioxide (b)nitrogen(c)none of these (d) carbon monoxide
2 answers
449 views
Find dy/dx when y=e^nx
1 answer
318 views
It was observed that due to poor nourishment the average weight of beetles reduced. If this continues in a number of generation,
1 answer
396 views
Given a planar electromagnetic wave in vacuum whose B-field is denoted by Bx = 0, Bz = 0, B_y = 66.7 × ?10?^(-8) sin 4?p?10?^6
1 answer
600 views
. An enzyme-catalyzed reaction was carried out in a 0.2M �Tris� buffer, pH 7.8. As a result of the reaction, 0.03 mole/liter
2 answers
2,922 views
If sin(x-20°)=cos(3x-10°),find x.
1 answer
557 views
If sin theta =a/b and theta lies in first quadrant, find all t-ratios.
1 answer
530 views
Determine the horizontal force P required to start the movement of the 200 lb blockup the 300inclined surface. The static
0 answers
879 views
(ii) A factory has two machines. Past records show that the first machine produces 40% of output and the second machine produces
1 answer
976 views
In sample of 1000 TV viewers, 330 watched a particular programme. Find 99% confidence limits for TV viewers who watch this
1 answer
1,076 views
how can i make informative speech give me guideline for that..
you can send me answer at mu id.
1 answer
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Answers (7)
3x
160°
devnagari
(d) carbon monoxide
GAACTGCATTGATA ______ 1 ______ 2 ______ 3 ______ 4 ______ 5 ______ 6 ______ 7 ______ 8 ______ 9 For a 6-mer, the probability of finding any particular sequence is 1/4*1/4*1/4*1/4*1/4*1/4 = 1/(46). The probability that any given 6-mer is present in 46
10,20,19
4 hours and 50 minutes
