Potassium chlorate is 75% pure 48 gram of oxygen would be produced from how much potassium chlorate

Answer 1

2KClO3 >> 2KCl +3O2

so one gets three moles of O2 for each two moles of the chlorate.
moles of O2=48/32=1.5
so we multiply that by the mole ratio: 1.5*2/3 to get the moles of the chlorate; but it is not pure, so
moles of impure chorate= 1/.75 * 1.5*2/3=4*3*2/3*3*4= 1.3333 moles
mass of that is 1.333*123 grams