AB is y = -2x+5
CD is y = -2x-8
the perpendicular bisector of AB meets CD at P=(-2.7,-2.6)
since C = P+(-1.3,2.6) that means
D = P+(1.3,-2.6) = (-1.4,-5.2)
Points, A(3, −1), B(2, 1) and C(−4, 0) are corners of an isosceles trapezium ABCD. Find coordinates of D if AB is parallel to DC.
2 answers
thanksss :)