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Point X is on line AC such that AX = 3 CX = 12. If <ABC = <BXA = 90 degrees, then what is BX?

Please help I have no idea how to approach this

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I know that <XBC=22.5

Triangles ABX and ACX are silimar (both have 90 degrees angle, while <CBX = 90 - ACX = 90 - (90 - <BAC) = <BAC), so BX/AX = CX/BX => BX^2 = 3*12 => BX = 6

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