Question

PLEASE SHOW WORK FOR ALL PROBLEMS, I WANT TO UNDERSTAND HOW TO DO IT, NOT JUST THE FINAL ANSWER :)

1. find all the zeros of the equation -3x^4+27x^2+1200=0

2. Use the Binomial Theorem to expand the binomial
(d-4b)^3

3. What is the equation of y=x^3 with the given transformations?
vertical stretch by a factor of 3, horizontal shift 4 units to the right, vertical shift 3 units down

THANK YOU SO MUCH :)

Answer 1

1. let t=x^2 (t>0)
the equation: -3t^2+27t+1200=0 ( you can solve this function by finding Delta)
<=>t=25 and t=-16( t>0)
<=>t=25 <=>x^2=25<=>x=-5,5
2. (a-b)^3=(a-b)(a-b)^2
=(a-b)(a^2-2ab+b^2)=a^3-3a^2b+3ab^2-b^3 ( then just apply)

Answer 2

3.stretch: 3x^3
right: 3(x-4)^3
down: 3(x-4)^3 - 3