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Question

solve the system by elimination

-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

Answer 1

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Answer 2

Subtract Eq2 from Eq1:
Diff. = 3y + 2z = 3.
Add Eq2 and Eq3:
Sum = 2y + 4z = 2.

3y + 2z = 3. Multiply by 2 and subtract.
2y + 4z = 2.

6y + 4z = 6.
2y + 4z = 2.
Diff. : 4y = 4.
Y = 1.
6y + 4z = 6,
6*1 + 4z = 6,
Z = 0.

Eq1: -2x + 2y + 3z = 0.
-2x + 2*1 + 3*0 = 0,
X = 1.

Solution = (x, y, z) = (1, 1, 0).

Answer 3

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Answer 4

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Answer 5

i needs helps Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

z
÷
12
=
9