clearly it is not a square.
192 has several factors:
4x48
6x32
8x24
12x16
...
so, which of those factor pairs adds up to half of 64?
Please help with trying to solve the following; in particular how to get the correct equation set up.
The perimeter of a square is 64 cm and the area of the square is 192 cm. What is the length of width of the rectangle?
Thank you for your help.
3 answers
Steve, thanks for responding, the question may have said rectangle. It was on a previous test and with a final coming up; I wanted to make sure I knew how to do. But I do have another one:
The question:
The perimeter of a rectangle is 34 inches and the area is 50 square inches. What is the length and the width of the rectangle.
Sorry about the previous question. Hope you can help. Thank you
The question:
The perimeter of a rectangle is 34 inches and the area is 50 square inches. What is the length and the width of the rectangle.
Sorry about the previous question. Hope you can help. Thank you
Hmmm.
xy=50
2(x+y) = 34
The only factor pairs of 50 are
1,50
2,25
5,10
None of those add up to 17, so the sides will not be integers. To find them, you will need to solve a quadratic equation:
x+y=17
x + 50/x = 17
x^2-17x+50 = 0
Now just use the quadratic formula.
xy=50
2(x+y) = 34
The only factor pairs of 50 are
1,50
2,25
5,10
None of those add up to 17, so the sides will not be integers. To find them, you will need to solve a quadratic equation:
x+y=17
x + 50/x = 17
x^2-17x+50 = 0
Now just use the quadratic formula.