Please help!:( What mass of copper would be produced by the reduction of copper(II) ions during pas- sage of 1 ampere of current through a solution of copper(II) sulfate for 89 minutes?

Answer 1

coulombs = A X S
convert 89 mins to seconds

____ c (1 c/1 mol e-) = ___ mol e-
____ mol e- (1 mol/2 e- cu 2+) = mol cu
mol cu x MW cu = g cu

Answer 2

I got 5340. Is that right?