Please help!

Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning. Do not use algebra
Thanks!

2 answers

900cal=400grams*.092cal/C*delatTemp

solve for DeltaTemp.

Do not use algebra? You have to be kidding. You could estimate it, 400x.1=40, and 400/40 is about 10C.
oops, the danger of estimated in the head.

900/40 is about 23C

Use algebra, and a calculator.