The temperature of a liquid during an experiment can be modeled by the function f(x)=3.8cos(πx20)+2.2 , where f(x) is the temperature in °C and x is the number of minutes into the experiment.
What is the lowest temperature the liquid reached during the experiment?
Round to the nearest tenth of a degree if needed.
Use 3.14 for π .
Enter your answer in the box.
SORRY I POSTED THE WRONG QUESTION BUT CAN YOU HELP MEWITH THAT ONE TOO PLEASE
PLEASE HELP ME WITH THIS QUESTION I DONT WANT TO FAIL AND I FEEL AS IF IM WRONG!
The average daily minimum temperature for Pablo’s hometown can be modeled by the function f(x)=15.3sin(πx6)+44.1 , where f(x) is the temperature in °F and x is the month.
x = 0 corresponds to January.
What is the average daily minimum temperature in June?
Round to the nearest tenth of a degree if needed.
Use 3.14 for π .
this is what my Algebra teacher taught me to do
2π/B=2π/π0/6
cross out the π and I'm left with 2,0, and 6. She's telling me to multiply them so i did and got 0.
This is the part thats bothering me cuz i believe im wrong!
4 answers
f(x)=15.3sin(π*x*6)+44.1
For January, x = 0
f(0) = 15.3sin(π*0*6) + 44.1
= 15.3sin(0) + 44.1
sin(0) = 0
f(0) = 44.1
Now, for June, x = 5
f(5) = 15.3sin(π*5*6) + 44.1
= 15.3sin(30π) + 44.1
= 15.3sin(15*2π) + 44.1
= 15.3sin(2π) + 44.1
= 44.1
Are you sure you've got the correct equation? As it is now, the temperature would be 44.1 degrees for each month.
For January, x = 0
f(0) = 15.3sin(π*0*6) + 44.1
= 15.3sin(0) + 44.1
sin(0) = 0
f(0) = 44.1
Now, for June, x = 5
f(5) = 15.3sin(π*5*6) + 44.1
= 15.3sin(30π) + 44.1
= 15.3sin(15*2π) + 44.1
= 15.3sin(2π) + 44.1
= 44.1
Are you sure you've got the correct equation? As it is now, the temperature would be 44.1 degrees for each month.
wait hold on thank you for explaining the first one to me but i meant to post this question ---> The temperature of a liquid during an experiment can be modeled by the function f(x)=3.8cos(πx20)+2.2 , where f(x) is the temperature in °C and x is the number of minutes into the experiment.
What is the lowest temperature the liquid reached during the experiment?
Round to the nearest tenth of a degree if needed.
Use 3.14 for π .
Enter your answer in the box.
and i got the answer 0 for that question which i belive im wrong. I looked at the recordings that my teacher sent and they didnt help at all. sorry im so stressed i dont want to fail.
What is the lowest temperature the liquid reached during the experiment?
Round to the nearest tenth of a degree if needed.
Use 3.14 for π .
Enter your answer in the box.
and i got the answer 0 for that question which i belive im wrong. I looked at the recordings that my teacher sent and they didnt help at all. sorry im so stressed i dont want to fail.
f(x)=3.8cos(πx20)+2.2
cos(x) has a minimum value of -1
so, f(x) has a minimum value of
2.2 + 3.8(-1) = -1.6
cos(x) has a minimum value of -1
so, f(x) has a minimum value of
2.2 + 3.8(-1) = -1.6
1 answer