Please help me to solve this problem.

A body is projected vertically upwards with a velocity 20m/s. find the maximum height reached by the body.(g=10m/sec2)

6 answers

Enough already !
usquare divided by 2g
therefore 400/20 is 20 metres
thankyou
Let initiql velocity be 10^2 and final velocity be 0 and acceletation due to gravity be -10m/s^2

By using formula
V^2- u^2=2*a*S
0^2- 10*2 =2*-10S
-100=-20S
-100/-20=s
5m=s
Let initiql velocity be 20^2 and final velocity be 0 and acceletation due to gravity be -10m/s^2

By using formula
V^2- u^2=2*a*S
0^2- 20^2=2*-10S
-400=-20S
-400/-20=s
20m=s
Let initial velocity be 20^2 and final velocity be 0 and acceletation due to gravity be -10m/s^2

By using formula
V^2- u^2=2*a*S
0^2- 20^2=2*-10S
-400=-20S
-400/-20=s
20m=s
H=u^2/2g
=20×20/2×10
=20m/s
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