Since acceleration is the derivative of velocity, you have to take the slope between 15 and 29.
f(b)-f(a)/b-a
(87-45)/(29-15)=42/14= 3 m/s2
Please help me!!! The table below represents the velocity of a car as a function of time:
time Velocity
seconds (m/s)
x f (x)
15 45
22 66
29 87
36 108
The average rate of change of the function between x = 15 to x = 29 is __________m/s2 and represents the car's acceleration
2 answers
Since acceleration is the derivative of velocity, you have to take the slope between 15 and 29.
f(b)-f(a)/b-a
(87-45)/(29-15)=42/14= 3 m/s2
That means that 3m/s2 is 3 meters per second
f(b)-f(a)/b-a
(87-45)/(29-15)=42/14= 3 m/s2
That means that 3m/s2 is 3 meters per second
4 answers