P1/T1 P2T2
610/273 = 760/T2
Solve for T2 (in kelvin).
Note that I changed 1 atm to 760 torr to agree with the 610 torr. Units must match.
Please help me get started, i'm not asking for the answer, just some help!
A gas occupies 340mL at 273 K and 610 torr. What final temperature would be required to increase the pressure to 1 atm, the volume being held constant?
3 answers
Ok so i'm confused because T=273K is already in Kelvin.
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