same old conservation of momentum
at first
p = 2 *1 + m * 4.4
at the end
p = (2+m) * 1.5
so
(2+m)(1.5) = 2 + 4.4 m
3 + 1.5 m = 2 + 4.4 m
etc
Please help!! I know how to work the problem to find velocities, but this one has me stumped!
A 2.0kg block slides along a frictionless surface at 1.0m/s . A second block, sliding at a faster 4.4m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 1.5m/s. What was the mass of the second block?
1 answer
1 answer