r = 9*10^2
v = (4/3) pi r^3
v = (4/3)(3.14159) (729) * 10^6
well, a bit less than 4*800* 10^6
3200*10^6 is around 3 * 10^9
Please help I don't know how to solve this
Suppose a spherical asteroid has a radius of approximately 9.0 × 102 m. Use the formula start fraction 4 over 3 end fraction symbol pir3 to find the approximate volume of the asteroid.
A. 3.05 × 106 m3
B. 1.95 × 1011 m3
C. 3.05 × 109 m3
D. 1.13 × 104 m3
1 answer
2 answers