suppose a spherical asteroid has a radius of approcimately 3.2x10^3 m. Use the formula 4/3*pie* r^3 to find the approcimate volume of the asteroid

1.37 x 10^11
4.02 x 10^4
1.35 x 10^12
2.4 x 10^12

d?

2 answers

it says approximate so no calculator :)
well 4/3 pi is about 4
so
4 r^3
4 * 3.2 * 3.2 *3.2 * 10^9
4 * a bit over 27 call it 30 * 10^9
around 120 * 10^9
1.2 * 10^11
oh look 1.37 * 10^11
The others are far away :)
what is the answer?