Suppose you are tossing an apple up to a friend on a third story balcony. After t seconds, the height of the apple in feet is given by h = -16t^2 + 38.4t + .96. Your friend catches the apple just as it reaches its highest point. How long does the apple take to reach your friend, and at what height above the ground does your friend catch the apple?
From the height formula, the initial upward speed is 38.4 ft./sec.
From Vf = Vo - gt, Vf = 0, Vo = 38.4 ft./sec. and g = 32 ft/sec.^2.
0 = 38.4 -32t making t = 1.2 sec.
Therefore, h = 38.4(1.2) - 16(1.2)^2 + .96 = 24 ft.
Time to friend is 1.2 sec. at h = 24 ft.
Please help I don't have any clue on how to solve this problem!!! Please help!
Suppose you are tossing an apple up to a friend on a third story balcony. After t seconds, the height of the apple in feet is given by h = -16t^2 + 38.4t + .96. Your friend catches the apple just as it reaches its highest point. How long does the apple take to reach your friend, and at what height above the ground does your friend catch the apple?
5 answers
how did you get g equaled to 32ft/sec^2? I'm a little confused on that part?
How did you get 32ft for g?
The earth's surface acceleration due to gravity is g = 32.2 ft/sec^2, rounded off to 32.
(01.05)
What is the slope-intercept form equation of the line that passes through (5, 7) and (8, 22)? (1 point)
y = −5x + 18
y = 5x − 18
y = −5x − 18
y = 5x + 18
What is the slope-intercept form equation of the line that passes through (5, 7) and (8, 22)? (1 point)
y = −5x + 18
y = 5x − 18
y = −5x − 18
y = 5x + 18