y-1nt. = 3, P(3, 4).
Y = mx+b.
4 = m*3 + 3
m = 1/3.
Eq1: Y = (1/3)x + 3. Graph: P1(0, 3), P2(3, 4)
Eq2: Y = -2x + 2. Graph: P1(0, 2), P2(3, -4).
The point where the lines intersect is the solution.
Standard form:
Eq1: x - 3y = -3.
Eq2: 2x + y = 2.
Please help ASAP!!!
Graph the following lines given the equation or y-intercept with an ordered pair, with a y-intercept of 3 and an ordered pair of (3, 4).
Line 1: y-intercept: 3 ordered pair: (3, 4)
Line 2: y=-2x+2
2 answers
Correction:
Standard form
Eq1: x - 3y = -9.
Eq2: 2x + y = 2.
Standard form
Eq1: x - 3y = -9.
Eq2: 2x + y = 2.