points on circle:
(0,0), (5,0)
find intersections of lines for third point on circle
2(y) + 3 y = 10
5 y = 10
y = 2 then x = 2
so third point is (2,2)
(0,0) (5,0) (2,2)
(x-a)^2 + (y-b)^2 = r^2
plug and chug
a^2 + b^2 = r^2
(5-a)^2 + b^2 = r^2
(2-a)^2 +(2-b)^2 = r^2
a^2 + b^2 = 25 -10a + a^2 + b^2
10 a = 25
a = 2.5
etc
please he lp
Find the equation of a circle circumscribes a triangle determined by the line y= 0 , y= x and 2x+3y= 10
this is my first timein this website please help me need it badly my teacher will be angry at me so much
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