log4(m-3)+ log4(m+3) =2
log4[(m+3)(m-3)] = log4(m^2-9) = 2 = log4(16)
m^2 -9 = 16
m = 5
<<Use common logarithms to approximate log9(207) to four decimal places.
Answer: 2.4270>>
log9(207)*log10(9)= log10(207)
log9(207) = 2.31597/0.95424 = 2.4270
I don't have time to do all 10. Fewer questions per post would be appreciated, even it you just want them checked.
Please check the following:
Solve log4(m-3)+ log4(m+3) =2
Answer: 1
Solve 6^3n=43^5n-4
Answer: 1.1202
Solve 5^2x+1>=50
Answer:x>=4.5000
Use common logarithms to approximate log9(207) to four decimal places.
Answer: 2.4270
Ealuate: In e^-9x
Answer: -9x
Solve 4+3e^5x = 27
Answer: 1.53333
Solve IN (x+5) >= 2.
Answer: x>= 2.3891
A particular compound decays according to the equation y=ae^-0.0974t, where t is in days. Find the half life of this compound.
Answer: about 7.1 days
At a large town with a large convention center, the cost of a hotel room has increased 5.1% annually. If the average hotel room cost $48.00 in 1980 and this growth continues, what will an average hotel room cost in 2012? Use y=a(1+r)^t and round to the nearest cent.
Answer:$235.79
Thanks.
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