Ask a New Question

physics:the notes at 110Hz has two strings at this pitch. if 1 slips from its normal tension of 600N to 540N what beat frequency would be heard when the two strings are stuck simultaneously?

1 answer

540/600 * 110 = 99 Hz.

Fb = 110 - 99 = 11 Hz. = Beat Freq.

Ask a New Question or answer this question.

Similar Questions

physics:the notes at 110Hz has two strings at this pitch. if 1 slips from its normal tension of 600N to 540N what beat frequency
1. 0 answers
when tuning a piano, amusician plays a note that should be at 110Hz while at the same time tapping a 110Hz tuning fork and
1. 1 answer
when tuning a piano, amusician plays a note that should be at 110Hz while at the same time tapping a 110Hz tuning fork and
1. 2 answers
Question The bass staff shows (1 point) Responses notes that are lower in pitch. notes that are lower in pitch. notes that are
1. 1 answer

more similar questions