when tuning a piano, amusician plays a note that should be at 110Hz while at the same time tapping a 110Hz tuning fork and holding it next to the strings. He hears beats at 4Hz.

Question

when tuning a piano, amusician plays a note that should be at 110Hz while at the same time tapping a 110Hz tuning fork and holding it next to the strings. He hears beats at 4Hz. 
(A) state and explain what frequencies the piano could be producing 
(b) explain how the musician now finishes tuning his piano
(C) Draw a sketch graph to show the resultant sound as a variation in displacement against time. Label the time axis with values.

Bami Haile · Accepted Answer

What about question c ?

Henry · Answer

a. F1 = 110-4 = 106 Hz. = The difference freq. F2 = 110+4 = 114 Hz = The sum freq. b. Adjust strings until the notes cannot be heard.