physical science
it is found that 40 ml of a 0.5mol.dm^-3 sodium hydroxide solution is needed to neutralise 20mol of the vinegar. calculate the pH of the sodium hydroxide solution
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A weird question; i.e., all of that information about vinegar but the pH of the NaOH has nothing to do with it.
However, pOH = -log(OH^-) = -log(0.5M) = ?
Then pH + pOH = pKw = 14. You know pOH and pKw, solve for pH. I get about 13.7.
However, pOH = -log(OH^-) = -log(0.5M) = ?
Then pH + pOH = pKw = 14. You know pOH and pKw, solve for pH. I get about 13.7.
1 answer