More dilute sodium hydroxide solutions are often prepared from a sastuated sodium hydroxide soltuion that's is 52.0% by mass and has a density of 1.48 g/mL. Calculate the volume, in liters, of this solution needed to prepare 35.0 L if 0.125 M sodium hydroxide?

Answer 1

52.0% w/w means 52 g NaOH/100 g solution.
Convert 52 g NaOH to moles. moles = grams/molar mass.
Use the density to convert 100 g soln to mL, then to L. Then molarity = moles/L soln. Finally, mL x M = mL x M.