To determine how the covalent bonds form in phosphorus trichloride (PCl₃), we first need to analyze the electron configurations of phosphorus and chlorine and how they will share their electrons.
Phosphorus (P) has 5 valence electrons (2 in the inner shell and 5 in the third circle). Chlorine (Cl) has 7 valence electrons (2 in the inner shell, 8 in the middle, and 7 in the outer shell).
In phosphorus trichloride, phosphorus will form three covalent bonds with three chlorine atoms. Each chlorine atom will share one of its valence electrons with phosphorus to complete its octet, while phosphorus shares one of its five valence electrons to achieve a stable configuration.
Given the possible diagrams:
- The first option indicates phosphorus sharing two pairs with one chlorine and a pair with each of the other two chlorines, which is incorrect as phosphorus only forms three bonds.
- The second option suggests phosphorus has four shared pairs, which is also incorrect.
- The third option shows phosphorus bonding with three chlorines and still having two unshared electrons (lone pairs) on phosphorus, which aligns with phosphorus's valency and its electron configuration.
- The fourth option also indicates phosphorus sharing three pairs, but does not properly represent the lone pair on phosphorus.
The best representation for covalent bonding in phosphorus trichloride is the third option, as it accurately depicts phosphorus with three bonds to three chlorine atoms, while also retaining two unshared electrons (lone pairs) on phosphorus.
Therefore, the most appropriate diagram is the third option.