To understand how covalent bonds form in phosphorus trichloride (PCl₃), we can analyze the electron configurations of phosphorus and chlorine.
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Phosphorus (P) has 5 valence electrons (as indicated by the 5 small green spheres in the outermost circle). To achieve a stable octet, phosphorus can share three of its electrons with three chlorine atoms.
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Chlorine (Cl) has 7 valence electrons (as indicated by the 7 small green spheres in the outermost circle). Each chlorine atom needs 1 additional electron to complete its octet.
In the bonding process:
- Each chlorine atom shares one of its 7 valence electrons with phosphorus.
- Phosphorus shares one of its 5 valence electrons with each of the three chlorine atoms.
Thus, in the covalent bonding of PCl₃:
- Phosphorus forms three single covalent bonds with three chlorine atoms by sharing one electron from each.
Based on this, the correct representation of the formation of covalent bonds in phosphorus trichloride (PCl₃) would involve phosphorus sharing its electrons with each of the three chlorine atoms. This would likely be shown in a diagram that illustrates these shared pairs of electrons between phosphorus and each chlorine atom.
To summarize, the correct diagram would show phosphorus in the center sharing its outer electrons with three chlorine atoms, with appropriate indications of the shared electron pairs (representing the covalent bonds).