The balanced equation for this reaction is:
P4O10 + 6H2O → 4H3PO4
The number of grams of P4O10 required to make 1.50 L of aqueous solution containing 5.00% phosphoric acid by mass is:
1.50 L x 1.025 g/mL x 0.05 = 7.875 g
Phosphoric acid is prepared by dissolving phosphorus (V) oxide, P4O10, in water. What is the balanced equation for this reaction? How many grams of P4O10 are required to make 1.50 L of aqueous solution containing 5.00% phosphoric acid by mass? The density of the solution is 1.025 g/mL.
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