The balanced equation for this reaction is:
P4O10 + 6H2O → 4H3PO4
To make 1.50 L of aqueous solution containing 5.00% phosphoric acid by mass, the amount of P4O10 required is:
1.50 L x 1.025 g/mL x 0.05 = 7.875 g
Phosphoric acid is prepared by dissolving phosphorus (V) oxide, P4O10, in water. What is the
balanced equation for this reaction? How many grams of P4O10 are required to make 1.50 L
of aqueous solution containing 5.00% phosphoric acid by mass? The density of the solution
is 1.025 g/mL
1 answer
1 answer