Question

Perform the indicated operations and write the answer in the form a + bi, where a and b are real numbers.

Problem #1 (3+2i)^2
Problem #2 i^3 - i^2

Answer 1

Notice the following pattern of powers of i
i = √-1
i^2 = √-1√-1 = -1
i^3 =i(i^2) = i(-1) = -i
i^4 = (i^2)(i^2) = (-1)(-1) = +1
i^5 = i(i^4) = i(1) = i
Can you see the pattern

for your first question , just expand it like you would (a+b)^2, then replace the powers of i

for the second, you should be able to do it following the above patterns

Answer 2

thanks...can I ask u to tell me if I'm correct when I do the problems please and repost back?

Answer 3

Reiny...

are these the correct answers??

problem #1: (3+2i)^2=
(a+b)^2=
(3+2times-1)=
(3+1)^2=
4^2= 16

problem #2: i^3-i^2=
a-b=
-i- -1

??????????????????????????

Answer 4

No, not right

(3+2i)^2= 9+12i+4i^2= 9+12i-4=5+12i
check that.

Answer 5

is this the answer bob purley??? thanks for your help!!

Answer 6

You need to check it and answer for yourself it is it right.

Answer 7

it makes sense now...thanks!!

Answer 8

PROBLEM 2....

i^3 - i^2=
-i + the square root of -1^2=
-i + 1i

is this correct?

Answer 9

Perform all operations. Give your answer in
a + bi
form.
4(2 − i)