Percentage formula of oxygen in sodium trioxonitrate(v)

8 answers

Please I need answer to the question
percent of what?
mass?
no. of atoms?

in any case, percent is (amount you are interested in) / total * 100%
Pleeeeeease
Na=23N=14, O=16
I am waiting someone please give me the answer
what, still no effort on your part? If you want the % of O atoms, then that is just
16/(23+14+16) = 16/53 = 0.30 = 30%

if you want % mass, then just multiply all the numbers by their respective atomic weights.
Na=23N=14, O=16
Thx
Note: %O = [(3*16)/(85)]*100