Percentage mass of sodium in sodium trioxonitrate(v) Na=23, N=14,O=16

Answer 1

Is It, 23+14 +48=85
23/85*100
14/85*100
16/85*100

Answer 2

Any answers🤨😁

Answer 3

Anyone😥

Answer 4

Someone please give me an answer

Answer 5

Is the answer to the question correct

Answer 6

Any anwers

Answer 7

No one is answering me

Answer 8

NaNO3. molar mass NaNO3 is 85.
So (23/85)*100 = ?%Na but I would prefer you name NaNO3 simply sodium nitrate.