Pb goes from 4+ on the left to 2+ on the right.
PbO2. You know O is 2-, two of them makes 4- so Pb must be + in order for the comound to be zero. All compounds are zero.
On the right you know SO4^2- in PbSO4 is 2- so Pb must be 2+. You don't know how to determine oxidation states. Here is a very good site. Specifically you want to look at #2.
https://www.chemteam.info/Redox/Redox.html
PbO2 + 4H+ + SO42– + 2e– → PbSO4 +2H2O
How does the oxidation number for lead (Pb) change?
1 answer
2 answers