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for the redox reaction given in the chemical equation Pb(OH)4^2- (aq) + ClO- (aq) --> PbO2 (s) + Cl- (aq)

For the oxidation half reaction I got Pb(OH)4^2- (aq) --> PbO2 (s) + 2H2O (l) + 2e-

For the reduction half reaction I got 2e- + 2H2O(l) + ClO-(aq) --> Cl- (aq) + H2O (l) + 2OH- (aq)

I'm having trouble figuring out the Ecell and delta Grxn^o. Could you please help?

1 answer

Look up the reduction potential for PbO2 ==> Pb(OH)4^2- and reverse the sign.
Look up the reduction potential for the ClO^- ==> Cl^-. Add the oxidation E and redn E to find Eocell.

Then dGrxn = -nFE