Pb(aq)2+ + 2e- → Pb(s) Ero = - 0.13 V
Sc(aq)3+ + 3e- → Sc(s) Ero = - 2.02 V
a) Write a balanced chemical equation for a spontaneous reaction involving these half reactions.
b) Explain your rationale for the reaction going in this direction.
1 answer
I don't know what Ero stands for. These are reductions that you've written. To make a spontaneous reaction you want Ecell to be + so you want to reverse the most negative reaction and add the other to it. See if you can do that. Remember you ant to have the electrons to balance so you will need 2*3e and 3*2e.