c. The equation is nuts. It should read:
work done=changeinKE+changeinPE+changeinThermal
you have the change in KE, the change in PE is zero, you know work done, so you calculate the changeinThermal.
As a side note, b is wrong, F=45, not 450N
PARTS C AND D ARE WHAT I'M HAVING TROUBLE WITH.
a tobaggan of mass 20kg is dragged horizontally across snow by someone who exerts a force of 45N. the tobaggan travels 8m under the action of the force and has a final speed of 2.6 m/s.
a)calculate the actual kinetic energy of the tobaggan based on its speed
Ek=1/2mv^2
=1/2(20)(2.6)
=67.6J
b)Calculate the amount of work actually done on the tobaggan by the applied force
W=F X d
=450X8
=3600J
c)From your answers to parts a and b, calculate the amount of thermal energy generated.
Ethermal=Ekinetic + Epotential
I know that kinetic =67.6J from part a, but what would potential be?
d)Explain how this thermal energy was generated and state one effect it might have. ????? no idea of this one.
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