Ask a New Question
Search
Questions and answers by
Sarah N H
Questions (11)
the diagram shows a skateboarder starting a run from Position P (2.5m) at 2.6 m/s. The mass of the skateboarder system (boarde +
4 answers
870 views
DRWLS: PLEASE SEE ADDITIONAL INFO AT THE BOTTOM
its the second part of the question that I don't understand: according the graph
1 answer
1,123 views
PARTS C AND D ARE WHAT I'M HAVING TROUBLE WITH.
a tobaggan of mass 20kg is dragged horizontally across snow by someone who exerts
1 answer
526 views
its the second part of the question that I don't understand:
according the graph shown, the net force acting on an object varies
2 answers
580 views
according the graph sown, the net force acting on an object varies wth the object's displacement.calculate the work down by the
0 answers
545 views
Cathy takes the bus home from work. In her hand she holds a 2 kg cake box, tied together with a string. As she ascends the steps
1 answer
651 views
Sam is sitting in her fishing boat watching a trout swim below the surface. She guesses the apparent depth of the trout at 2.0m.
1 answer
569 views
Sam is sitting in her fishing boat watching a trout swim below the surface. She guesses the apparent depth of the trout at 2.0m.
2 answers
670 views
Sam is sitting in her fishing boat watching a trout swim below the surface. She guesses the apparent depth of the trout at 2.0m.
3 answers
731 views
Sam is sitting in her fishing boat watching a trout swim below the surface. She guesses the apparent depth of the trout at 2.0m.
5 answers
604 views
A guitar string 60 cm in length, with a diameter of 1.4 mm and a tension of 289 N, emits a note with a frequence of 147 Hz. Find
2 answers
708 views
Answers (6)
I have drawn them all, but just want to make sure that I should be dividing 2 metres into tan1 (which is 32, to give me a real depth of 3 metres. Can you please verify that?
Bob: your website, when I rearrange the formula, would be real depth = X/tani...What is the 'x" in my problem? DRWLS: I am solving for the actual depth, the apparent depth is given...do I still use your same formula? Thankyou both.
I figured out the angle to be 32 degrees but still don't know how to figure out the height...
* I meant, NO underwater height is given
Bob - thanks for the reply. I have figured out the angle of incidence to be 32.3 degrees, but do not know how to caluclate the depth as underwater heigh is given (the only heigh is 1 m above water which I don't think i useful)...can you please help me
thanks Bob. Can you please help me with question A as well?
