To find the diagonal length of TV #1, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Let's label the length of TV #1 as A, and the width as B. We know that A = 32 inches and B = 56 inches.
Using the Pythagorean theorem, we can find the diagonal length (C) of TV #1:
C^2 = A^2 + B^2
C^2 = 32^2 + 56^2
C^2 = 1024 + 3136
C^2 = 4160
To find C, we take the square root of both sides:
C = sqrt(4160)
C ≈ 64.49 inches
Therefore, the diagonal length of TV #1 is approximately 64.49 inches.
Now let's find the diagonal length of TV #2. We are given that the length is 39 inches and the width is 52 inches.
Using the same process as above, we find:
C^2 = 39^2 + 52^2
C^2 = 1521 + 2704
C^2 = 4225
Again, taking the square root of both sides:
C = sqrt(4225)
C = 65 inches
Therefore, the diagonal length of TV #2 is 65 inches.
By comparing the diagonal lengths, we can conclude that TV #2 is larger because its diagonal length (65 inches) is greater than the diagonal length of TV #1 (approximately 64.49 inches).
Part 1: You are deciding between purchasing two TVs at the store that cost the same price. One TV you physically measure to be 32 inches long by 56 inches wide. The second TV is in box only and advertises itself as 39 inches long by 52 inches wide. Knowing that TVs are traditionally measured by their diagonal length, you want to know which TV is the larger TV.(5 points)
How large is TV #1? The first TV measures
inches diagonally.
Question 2
Part 2: Now find the diagonal length of TV #2. Which TV is larger and why? You must show all of your work for Part 1 in here as well as your conclusion of Part 2 for full credit. (10 points)
1 answer
1 answer