part 1 of 3: A hawk flies in a horizontal arc of radius 9.9 m at a constant speed of 4.8 m/s. Find its centripetal acceleration. Answer in units of m/s^2.

Question

part 2 of 3: It continues to fly along the same horizontal arc but increases its speed at the rate of 1 m/s^2. Find the magnitude of acceleration under these new conditions. Answer in units of m/s^2.

Part 3 of 3: Find the direction of acceleration relative to the direction of motion under these conditions. Answer between -180 degrees and 180 degrees. Answer in unit of degrees.

Elena · Answer

(a) Centripetal (or normal) acceleration is a(c)= m•v²/R=… (b) Tangential acceleration a(τ)= 1 m/s² a=sqrt{a(c)² +a(τ)²}=... (c)tanα= a(c)/a(τ)= ..