(a) Centripetal (or normal)
acceleration is
a(c)= m•v²/R=…
(b) Tangential acceleration
a(τ)= 1 m/s²
a=sqrt{a(c)² +a(τ)²}=...
(c)tanα= a(c)/a(τ)= ..
part 1 of 3: A hawk flies in a horizontal arc of radius 9.9 m at a constant speed of 4.8 m/s. Find its centripetal acceleration. Answer in units of m/s^2.
part 2 of 3: It continues to fly along the same horizontal arc but increases its speed at the rate of 1 m/s^2. Find the magnitude of acceleration under these new conditions. Answer in units of m/s^2.
Part 3 of 3: Find the direction of acceleration relative to the direction of motion under these conditions. Answer between -180 degrees and 180 degrees. Answer in unit of degrees.
1 answer