paraphrase it
Since the calculated P-value for the interaction between the concrete and water amount is 0.995446 which are greater than the critical value of 0.05, we say that the test is not statistically significant and therefore the null hypothesis has to be rejected by accepting the alternate hypothesis. On the other hand, the calculated F-value for the interaction between the concrete and water amount is 0.047743 which is less than the f-critical value of 2.727765, we say that the null hypothesis has to be accepted and the alternate hypothesis will be rejected because the test is statistically significant.
1 answer
The interaction between the amount of concrete and water has a p-value of 0.995446, which is higher than the critical value of 0.05. As a result, we can conclude that the test is not statistically significant and we reject the null hypothesis in favor of the alternative hypothesis. On the other hand, the calculated F-value for this interaction is 0.047743, which is lower than the critical f-value of 2.727765. Therefore, we accept the null hypothesis and reject the alternative hypothesis because the test is statistically significant.
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