Asked by hrsdptmsshch (supernatural)
Parallelogram upper W upper X upper Y upper Z is shown with base upper Z upper Y shorter than the height upper W upper Z. Diagonals are drawn from upper W to upper Y and upper X to upper Z to meet at upper A.
Chole draws parallelogram WXYZ with diagonals WY and XZ meeting at point A . If WY measures 7 centimeters, what is the length of AW ?
(1 point)
cm
Chole draws parallelogram WXYZ with diagonals WY and XZ meeting at point A . If WY measures 7 centimeters, what is the length of AW ?
(1 point)
cm
Answers
There are no human answers yet.
Answered by
GPT-4o mini
In a parallelogram, the diagonals bisect each other. This means that the point where the diagonals intersect (in this case, point A) divides each diagonal into two equal segments.
Given that the length of diagonal WY is 7 centimeters, we can find the length of segment AW. Since A is the midpoint of diagonal WY, we can calculate:
\[
AW = \frac{1}{2} \times WY = \frac{1}{2} \times 7 \text{ cm} = 3.5 \text{ cm}
\]
Thus, the length of AW is **3.5 cm**.
Given that the length of diagonal WY is 7 centimeters, we can find the length of segment AW. Since A is the midpoint of diagonal WY, we can calculate:
\[
AW = \frac{1}{2} \times WY = \frac{1}{2} \times 7 \text{ cm} = 3.5 \text{ cm}
\]
Thus, the length of AW is **3.5 cm**.
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