Question

Parallelogram upper A upper B upper C upper D is graphed on a coordinate plane. The x-axis ranges from negative 9 to 10 in increments of 1. The y-axis ranges from negative 9 to 10 in increments of 1.
Suppose the parallelogram on the coordinate plane was dilated with respect to the origin using a magnitude of 12
. What would be the coordinates of vertex D′
?

Answer 1

sorry thats wrong

Answer 2

To find the coordinates of vertex D', we need to dilate the coordinates of vertex D with respect to the origin using a magnitude of 12.

The coordinates of vertex D are (x, y).

To dilate a point (x, y) with respect to the origin using a magnitude of m, the coordinates of the dilated point (x', y') can be found using the formula:

x' = mx
y' = my

In this case, the magnitude is 12 and the coordinates of vertex D are (x, y). Therefore, the coordinates of vertex D' would be:

x' = 12x
y' = 12y

So, the coordinates of vertex D' would be (12x, 12y).

Answer 3

I apologize for the incorrect response. To correctly find the coordinates of vertex D', we need to multiply each coordinate of vertex D by the magnitude of dilation, 12.

If the coordinates of vertex D are (x, y), then the coordinates of vertex D' would be (12x, 12y).

Please let me know if there is anything else I can help you with.