In a parallelogram, the diagonals bisect each other. This means that the lengths of the segments created by the intersection of the diagonals are equal.
Given that \( RV = y + 18 \) and \( TV = 3y - 10 \), we can set these equal to one another since \( RV = VT \):
\[ y + 18 = 3y - 10 \]
To solve for \( y \), we can rearrange the equation:
\[ 18 + 10 = 3y - y \] \[ 28 = 2y \] \[ y = 14 \]
Now, we can find the lengths of \( RV \) and \( TV \):
\[ RV = y + 18 = 14 + 18 = 32 \quad \text{units} \] \[ TV = 3y - 10 = 3(14) - 10 = 42 - 10 = 32 \quad \text{units} \]
Since the diagonals bisect each other, we have:
\[ RT = RV + VT = RV + RV = 2RV = 2(32) = 64 \quad \text{units} \]
Thus, the length of diagonal \( RT \) is:
\[ \boxed{64} \quad \text{units} \]